find a and b if 3 + underoot 2/ 3 -2 underoot 2 = a+b underoot 2
Aaryadeep:
hi anu
is my answer is right ?
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(3+√2)/(3-2√2)
Rationalising factor =3+2√2
→(3+√2)/(3-2√2)×(3+2√2)/(3+2√2)
→(3+√2)(3+2√2)/(3-2√2)(3+2√2)
→3(3+2√2)+√2(3+2√2)/(3²-(2√2)²)
→9+6√2+3√2+2(√2²)/(9-4(√2²))
→[9+9√2+2(2)]/(9-4(2))
→13+9√2/9-8
→13+9√2/1
→13+9√2 = a+b√2
By comparing,
a=13,b=9
Rationalising factor =3+2√2
→(3+√2)/(3-2√2)×(3+2√2)/(3+2√2)
→(3+√2)(3+2√2)/(3-2√2)(3+2√2)
→3(3+2√2)+√2(3+2√2)/(3²-(2√2)²)
→9+6√2+3√2+2(√2²)/(9-4(√2²))
→[9+9√2+2(2)]/(9-4(2))
→13+9√2/9-8
→13+9√2/1
→13+9√2 = a+b√2
By comparing,
a=13,b=9
their was also a+b underoot 2
ok
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