find a and b if √5+√3\√5-√3 =a-√15b
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Answered by
6
Hlo Buddy here is your ans
I am sorry first but according to your question
there are two variable and one equation so we cannot find complete the ans
there the ans is drawn in term of variable
√5+√3\√5-√3=a-√15b
taking l.c.m
√5×√3+√3-√3×√5=a√5-√15×√5b
cancel the value if anyone are cancel out
√3=a√5-5√3b
(√3+5√3b)/√5=a
◆◆◆◆◆ Be Brainly ◆◆◆◆◆◆
nehajain125
I am sorry first but according to your question
there are two variable and one equation so we cannot find complete the ans
there the ans is drawn in term of variable
√5+√3\√5-√3=a-√15b
taking l.c.m
√5×√3+√3-√3×√5=a√5-√15×√5b
cancel the value if anyone are cancel out
√3=a√5-5√3b
(√3+5√3b)/√5=a
◆◆◆◆◆ Be Brainly ◆◆◆◆◆◆
nehajain125
PrayagKumar:
mst answer
Answered by
10
heyya!!!!
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SOLUTION:
Rationalizing L.H.S,
=> √5+√3/√5-√3 × √5+√3/√5+√3 = a+b√15
=> (√5+√3)²/(√5)²-(√3)² = a+b√15
=> 5+3+2√15/5-3 = a+b√15
=> 8+2√15/2 = a+b√15
=> 2(4+√15)/2 = a+b√15
=> 4+√15 = a+b√15
therefore, a = 4 and b = 1
______________________________________
hope it helps!!!!^_^
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SOLUTION:
Rationalizing L.H.S,
=> √5+√3/√5-√3 × √5+√3/√5+√3 = a+b√15
=> (√5+√3)²/(√5)²-(√3)² = a+b√15
=> 5+3+2√15/5-3 = a+b√15
=> 8+2√15/2 = a+b√15
=> 2(4+√15)/2 = a+b√15
=> 4+√15 = a+b√15
therefore, a = 4 and b = 1
______________________________________
hope it helps!!!!^_^
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