Math, asked by Dhanesh3042, 9 months ago

Find a and b if a square is equal to b cube is equal to k

Answers

Answered by ItzMADARA
1

equation A) is the main equation to get the value of a/b+b/a,

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so that

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)3a^4b^2+3b^4a^2=2(a^3b^3)

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)3a^4b^2+3b^4a^2=2(a^3b^3)now take (ab)^2  as common

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)3a^4b^2+3b^4a^2=2(a^3b^3)now take (ab)^2  as common3(a/b+b/a)=2

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)3a^4b^2+3b^4a^2=2(a^3b^3)now take (ab)^2  as common3(a/b+b/a)=2a/b+b/a=2/3

equation A) is the main equation to get the value of a/b+b/a,(a^2+b^2)^3=(a^3+b^3)^2 --->A)now you are required to open above equation using ,(a+b)³ and (a+b)² formula,so thata^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)3a^4b^2+3b^4a^2=2(a^3b^3)now take (ab)^2  as common3(a/b+b/a)=2a/b+b/a=2/3so that correct value of a/b+b/a is 2/3

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