Question

find a and b if root2+root3/3root2-2root3 =a-b root 6​

Answer 1

Answer:

(√2+√3).(3√2 -2√3) = a - b√3√2.

First rationalise it by multiplying & dividing the LHS with the conjugate of the denominator.

LHS : [(√2+√3).(3√2 -2√3)] / [(3√2 -2√3).(3√2+2√3)]

= [(√2+√3).(3√2+2√3)] / [(3√2)² -(2√3)²]

= [6+(3+2)√6+6] / (18 -12)

= 2 + 5√6/6,

Then

2+(5/6)√6 = a - b√6.

By inspection you can know

a = 12; b = -5/6.

Step-by-step explanation:

hope it will help

Answer 2

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