Question

find a and b if sin(a+b) =root 3 ÷ 2 = cos (a-b) where a and b are acute angles

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Answer 1

Answer:

sin(a+b) = ✓3/2

a+b = sin inverse(✓3/2)

a+b = 60°..............equation 1

cos(a-b) = ✓3/2

a-b = 30°................equation 2

now solve the two equations by your own and u will get your answer

Answer 2

Answer:answer is down

Step-by-step explanation:sin(a+b) = ✓3/2

a+b = sin inverse(✓3/2)

a+b = 60°..............equation 1

cos(a-b) = ✓3/2

a-b = 30°................equation 2

now solve the two equations by your own and u will get your answer