Question

Find a and b if (x2+3x+2) is a factor of (x3+3x2 – 2ax+b).

Answer 1

Answer:

X-1=0

X=0+1

X=1

• X^3+3×2-2ax+B
• (1)^3+3×2-2a(1)+B
• 1+3×2-2a+B

4×2-2a+B eq ...1

X-2=0

x=0+2

X=2

• (2)^3+3×2-2a(2)+b
• 8+3×2-2a+B

11×2-4a+B eq...2

Subtacting from2to1

• 8-2a+b=0
• 22-4a+b=0
• (-) (+) (-)
• -14+2a=0
• 2a=14
• A=14/2
• =7

Now put the value of a in eq 1

• 8-2a+b=0
• 8-2(7)+b=0
• 8-14+b=0
• -6+b=0
• B=6

answer: a=7,

answer:b=6

Answer 2

Answer:

a=7

b=6

Step-by-step explanation: