find a and b if x3-ax3-13x-b has x2+2x-3 as a factor
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Let p(x) = x3 – ax2 – 13x + b be the given polynomial.
If (x – 1) and (x + 3) are the factors of p(x) then
p(1) = 0
and p(-3) = 0
p(1) = (1)3 – a(1)2 – 13(1) + b = 0
= 1 – a – 13 + b = 0
a – b = -12
p(-3) = (- 3)3 – a(- 3)2 - 13(- 3) + b = 0
= - 27 – 9a + 39 + b = 0
9a – b = 12 ….(2)
Solving (1) and (2) we get
a = 3
and b = 15
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