Question

Find 'a' and 'b' in -- 3/(√3-√2)=a√3-b√2

Answer 1

3/√3-√2 = a√3 - b√2

Rationalising the denominator

(3/√3-√2) ×(√3+√2/√3+√2)

(3√3+3√2) /3-2

3√3 + 3√2

Value of a = 3 and b = -3

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