Find a and b in the following equation. (root2 + root3)/3 root2 - 2 root3 = a-b root6.
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6
(√2+√3)/(3√2 - 2√3)
rationalizing it,
[(√2+√3)×(3√2 +2√3)]/[(3√2 - 2√3)×(3√2 + 2√3)]
=(6 +2√6 +3√6 +6)/[(18 - 12)]
=(12 + 5√6)/6
= 2 - (-5√6)/6
so, a = 2 and b = -5/6
rationalizing it,
[(√2+√3)×(3√2 +2√3)]/[(3√2 - 2√3)×(3√2 + 2√3)]
=(6 +2√6 +3√6 +6)/[(18 - 12)]
=(12 + 5√6)/6
= 2 - (-5√6)/6
so, a = 2 and b = -5/6
Answered by
0
Step-by-step explanation:
Answer
(V2+3/(3-12-203)
rationalizing it, [(V2+13)*(372 +2v3)/[((3v2 - 2v3)x(3v2
+23)]
=(6+216 +376 +6)[(18 - 12)] =(12+5V6)/6
= 2 - (-5 v 6)/6 so, a = 2 and b = -5/6
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