Question

find a and b in this equation root 3 + root 2 /root 3 - root 2 = a + b root 6

Answer 1

please reply about answer

Answer 2

$\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}} = a + b\sqrt{6}$
$= \frac{(\sqrt{3} + \sqrt{2})(\sqrt{3} + \sqrt{2})}{(\sqrt{3} - \sqrt{2})(\sqrt{3} + \sqrt{2})} = a + b\sqrt{6}$
$= \frac{(\sqrt{3} + \sqrt{2})^2}{(\sqrt{3}^2) - (\sqrt{2}^2)} = a + b\sqrt{6}$
$= \frac{(\sqrt{3} + \sqrt{2})^2}{3 - 2} = a + b\sqrt{6}$
$= \frac{(\sqrt{3} + \sqrt{2})^2}{1} = a + b\sqrt{6}$
$= (\sqrt{3} + \sqrt{2})^2 = a + b\sqrt{6}$
$= (\sqrt{3})^2 + (\sqrt{2})^2 + (2 * \sqrt{3} * \sqrt{2}) = a + b\sqrt{6}$
$= 3 + 2 + 2\sqrt{6} = a + b\sqrt{6}$
$= 5 + 2\sqrt{6} = a + b\sqrt{6}$

$a = 5$ and $b = 2$

Hope this may be helpful.