Math, asked by her2, 1 year ago

find a and b of 5+2√3/7+4√3=a_b√3

Answers

Answered by mathuanand1

we need to rationalize that,
(5+2√3)/(7+4√3)=a-b√3
35-20√3+14√3-24=a-b√3
11-6√3=a-b√3
so,
a=11
b=6.
####hope it is useful

sreedhar2: given a-b√3 not a+b√3

sreedhar2: Click on edit answer.. then you can edit

mathuanand1: ok tq

Answered by sreedhar2

5+2√3 / 7+4√3

Rationalising factor = 7-4√3.

By rationalisation,

= 5+2√3 (7-4√3) / (7+4√3) (7-4√3 )

= 35-20√3 + 14√3-24 / 7²-(4√3)². [ a+b (a-b) = a²-b²]

= 11 -6√3 / 49 - 48

= 11-6√3

Comparing this with a-b√3, we get

a = 11 and b = 6

:)

mathuanand1: no it is -6

mathuanand1: how u say that is 6

sreedhar2: no. yaar. check the question

sreedhar2: a-b√3 not a+b√3

mathuanand1: ok

mathuanand1: tq

sreedhar2: your welcome.

mathuanand1: umm

sreedhar2: pls do edit thw answer :)

mathuanand1: what i need to edit

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