Math, asked by shilmyshoy95, 10 months ago

find a and b so that the system of equations has infinte number of solutions (2a-1)x +3y-5 =0
3x+ (b-1) y - 2=0​

Answers

Answered by steja271996
1

Step-by-step explanation:

Sure I will answer it for you mate,

Infinite Solutions = a1/a2 = b1/b2 = c1/c2

(2a-1)/3 = 3/(b-1) = 5/2

(2a-1)/3 = 5/2

4a - 2 = 15

= a= 17/4

3(b-1)= 5/2

=5b-5 = 6

= b = 11/5

This is the answer friend please mark it as brain list..

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