Question

find a and b such that 12,a+b,2a,b are in arithmetic progression

Answer 1

Helloo!!

(a + b) - 12 = 2a - ( a + b) = b - 2a

(a + b) - 12 = 2a - a - b

a + b - 12 = a - b

2b = 12

So, b = 6

6 - 2a = 2a - ( a + 6)

6 - 2a = 2a - a - 6

6 - 2a = a - 6

12 = 3a

a = 4

then, a = 4 , b = 6

hope it helps!!

Answer 2

atq12=a+b
b!=12-a
2a=b
2a=12-a
a=12/3
a=4
therefore a=4
b=8