find a and b when √3-1/√3+1=a-b√3
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Hey
Here is your answer,
√3-1/√3+1 x √3-1/√3-1
= (√3-1)^2 / (√3)^2 - (1)^2
= 3+1-2√3 / 3-1
=4-2√3 / 2
= 2(2-√3) / 2
=2-√3
a-b√3 = 2-√3
a = 2
b = -1
Hope it helps you!
Here is your answer,
√3-1/√3+1 x √3-1/√3-1
= (√3-1)^2 / (√3)^2 - (1)^2
= 3+1-2√3 / 3-1
=4-2√3 / 2
= 2(2-√3) / 2
=2-√3
a-b√3 = 2-√3
a = 2
b = -1
Hope it helps you!
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