find A and Bif x=3\4 and x=-2 are roots of the equation ax+bx-6=0
Answers
Answer:
You could replace the value of x with the roots and solve the linear simultaneous equations for a and b. It is correct.Here is my solution:
x=3/4 or x=-2 which can be written mathematically as,
(x-3/4)(x+2)=0 Notice that both of the solutions of x, this equation holds true.
(x^2) +(5x/4)+ (3/2)=0
Multiplying by 4,
(4x^)+(5x)+6=0
a=4, b=5.
I am assuming that in the question, it is ax^2 and not ax, because it is impossible for a linear equation to have more than one solution.
Hope it helps. please mark branliest
Answer:
a=4 and b=5
Step-by-step explanation:
ax²+bx-6=0
9a/16+3b/4-6=0
9a+12b-96=0
3(3a+4b)=96
3a+4b=32---------------(1)
4a-2b=6
2a-b=3
multiply both side by 4
8a-4b=12---------------(2)
Adding eq.(1) and eq.(2)
3a+8a+4b-4b=32+12
11a=44
a=4
2a-b=3
2(4)-b=3
8-b=3
8-3=b
b=5
Hope this answer helps you...