Find a+b a^2+b^2=10 and a^3b-a^2b^2+ab^3=25
Answers
Answered by
1
a³b + a²b² + ab³ = 25
ab × (a² + ab + b²) = 25
ab × (10 + ab) = 25
a²b² + 10ab – 25 = 0
(ab–5)² = 0
ab = 5
(a+b)² = a²+b²+2ab = 10 + 2×5 = 20
a+b = sqrt(20) = 2×root(5)
ab × (a² + ab + b²) = 25
ab × (10 + ab) = 25
a²b² + 10ab – 25 = 0
(ab–5)² = 0
ab = 5
(a+b)² = a²+b²+2ab = 10 + 2×5 = 20
a+b = sqrt(20) = 2×root(5)
Similar questions