Question

find a, b and c so such that the following numbers are in AP a, 7, b, 23, c.​ pls give answer quickly.

Answer 1

Answer:

Since a, 7, b, 23 and c are in AP

∴ 7 - a = b - 7 = 23 - b = c - 23 = common difference

I II III IV

Taking second and third terms, we get

b - 7 = 23 - b

⇒ 2b = 30

∴ b = 15

Taking first and second terms, we get

7 - a = b - 7

⇒ 7 - a = 15 - 7

⇒ 7 - a = 8

∴ a = -1

Taking third and fourth terms, we get

23 - b = c - 23

⇒ 23 - 15 = c - 23

⇒ 8 = c - 23

⇒ 8 + 23 = c ⇒ c = 31

Hence, a = -1, b = 15, c = 31

Answer 2

Answer:

Use arithmetic mean formula...

Step-by-step explanation:

In an ap series.. it is known that :-  t1 + t3 / 2 = t2

So .. 7 + 23 / 2 = b = 15

Also in this question :-

a + b / 2 = 7 and b + c / 2 = 23

a + b = 14     and b + c  = 46

So. a = 14 - 15 = -1

      c = 46 - 15 =  31