Find a, b and c such that the following numbers are in A.Pa, 7, b, 23, c
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Answer:
Since a,7,b,23,c are in AP.
∴7−a=b−7=23−b=c−23 ....(1)
On taking 2
nd
and 3
rd
expression, we get,
b−7=23−b
⇒2b=30⇒b=15
On taking 1
st
and 2
nd
expression, we get,
7−a=b−7
⇒7−a=15−7⇒a=−1
Again, on taking 3
rd
and 4
th
expression, we get,
23−b=c−23
⇒23−15=c−23⇒c=31
Hence a=−1,b=15,c=31
∴a+b+c=−1+15+31=45
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