find a, b and c such that the following numbers are in ap : a, 7,b,23,c.
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Annyeong Army!
Hope this helps you :)
Step-by-step explanation:
For a, 7, b, 23, c… to be in AP it should satisfy the condition,
a5 - a4 = a4 - a3 = a3 - a2 = a2 - a1 = d
Where d is the common difference
7 - a = b - 7 = 23 - b = c - 23 …(1)
By equating,
b - 7 = 23 - b
2b = 30
b = 15 (equation 1)
And,
7 - a = b - 7
Substituting b value in equation 1
7 - a = 15 - 7
a = - 1
So we get,
c - 23 = 23 - b
c - 23 = 23 - 15
c - 23 = 8
c = 31
Here a = - 1
b = 15
c = 31
Therefore, the sequence - 1, 7, 15, 23, 31 is an AP.
Borahae!
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