Question

find a b and c with procedure

Answer 1

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Answer 2

Answer:a=-2/3,b=-13/9,c=10/9

Explanation:

-> 2a-3b=3

   3b=2a-3

   b=(2a-3)/3

-> -2a-3c=-2

   3c=-2a+2

   c=(-2a+2)/3

-> a+b+c=-1

   a+((2a-3)/3)+((-2a+2)/3)=-1

   3a+2a-3-2a+2=-3

   3a-1=-3

   3a=-2

   a=-2/3

hence substituting the value of 'a' we get,

   b=-13/9

   c=10/9