Question

Find (A+b+c)^3 ======

Answer 1

Hi friend here is your answer.

*************************************

(a+b+c)³=(a³+b³+c³)+3a(ab+ac+bc)+ 3b(ab+bc+ac) +3c(ac+bc+ab)−3abc

(a+b+c)³=(a³+b³+c³)+3(a+b+c)(ab+ac+bc)−3abc

(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]

########################

Answer 2

let a+b be x

(x+c)^3=x^3 +c^3+3x^2c+3xc^2

=(a+b)^3+c^3+3(a+b)^2c+3(a+b)×c^2

=a^3+b^3+c^3 +3ab(a+b)+3(a+b)^2c

+3(a+b)×c^2

=a^3+b^3+c^3+3(a+b){ab+ac+bc+c^2}

=a^3+b^3+c^3+3(a+b){a(b+c)+c(b+c)}

=a^3+b^3+c^3+3(a+b)(b+c)(a+c)


Hence, (a+b+c)^3=a^3+b^3+c^3+3*(a+b)(b+c)

(a+c)