find a+b+c if a^2+b^2+c^2=220 and ab+bc+ca =18
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Answered by
1
your answer
a2+b2+c2=220
Ab+BC+ca =18
apply
(a+b+c)2= a2+b2+c2+2(Ab+BC+ca )
(a+b+c)2=220+2(18)
(a+b+c)2=256
a+b+c=√256=16
a2+b2+c2=220
Ab+BC+ca =18
apply
(a+b+c)2= a2+b2+c2+2(Ab+BC+ca )
(a+b+c)2=220+2(18)
(a+b+c)2=256
a+b+c=√256=16
click thanks button at least
7871563520
Answered by
3
a^2+b^2+c^2+2ab+2bc+2ac= (a+b+c)^2
= 220+2(ab+BC+CA)
= 220 + 2(18)
=220+36
= 256 = (a+b+c)^2
√256 = a+b+c
16 = a+b+c
hope it helps u
= 220+2(ab+BC+CA)
= 220 + 2(18)
=220+36
= 256 = (a+b+c)^2
√256 = a+b+c
16 = a+b+c
hope it helps u
7871563520
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