Question

Find
a+b+c
if a^2+b^2+c^2=250
And
ab+bc+ca=3​

Answer 1

Answer:

±16

Step-by-step explanation:

We know  $a^{2}+b^{2}+c^2+2ab+2bc+2ca=(a+b+c)^2$

Multiply both sides by 2 in ab+bc+ca=3

we get 2ab+2bc+2ca=6

now by adding $a^2+b^2+c^2=250$ and 2ab+2bc+2ca=6

we get $(a+b+c)^2=256$

so a+b+c=±16