Question

Find a+b+c,if a2+b2+c2=74 and ab+bc+ac=61

Answer 1

Answer:a+b+c=37

Step-by-step explanation:a2+b2+c2=74

2(a+b+c)=74

74/2=(a+b+c)

(a+b+c)=37

Answer 2

The value of a + b + c is equal to 14.

Step-by-step explanation:

We have,

$a^2+b^2+c^2=74$ and $ab+bc+ac=61$

To find, the value of a + b + c = ?

We know that,

$(a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2(ab+bc+ca)$

Put $a^2+b^2+c^2=74$ and $ab+bc+ac=61$, we get

⇒ $(a+b+c)^{2}=74+2(61)$

⇒ $(a+b+c)^{2}=74+122$

⇒ $(a+b+c)^{2}=196$

⇒ $(a+b+c)^{2}=14^2$

⇒ a + b + c = 14

Hence, the value of a + b + c is equal to 14.