find a,b,c of quadratic equation 7/3-4x-x2=0
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Answer:
a=(-1), b=(-4), c=(7/3)
Step-by-step explanation:
First let's arrange it in standard form ax2+ bx + c =0
-x2 - 4x +7/3 = 0
so now we can easily sort outa a b and c
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