Find a:b:c when (1) a:b=4:7 and b:c=5:3, and (2) a:b=7 1/2:3 and 1 1/4:3
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How to do it ?
—— (1) : (2)
A:B = 2 : 3
B:C = 4 : 5
C:D = 6 : 7
A is the product of all terms appearing under column (1).
A = 2 x 4 x 6 = 48
B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.
B = 4 x 6 x 3 = 72
C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.
C = 6 x 3 x 5 = 90
D is the product of all terms appearing under column (2).
D = 3 x 5 x 7 = 105
=> A:B:C:D = 48:72:90:105
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