Find a cubic palynomial whose zeroes are -2 -3 and -1
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- we need to find the cubic polynomial.
- zero of required cubic polynomial are -2 , -3 and -1
Let α , β and Ɣ be the zeroes of the required cubic polynomial.
- Let α = -2
- β = -3
- Ɣ = -1
⇝(α + β + Ɣ) = -2 + (-3) + (-1)
⇝(α + β + Ɣ) = -2 - 3 - 1
⇝(α + β + Ɣ) = -6 ⠀....2)
⇝(αβ + βƔ + Ɣα) = -2 × (-3) + (-3) × (-1) + (-1) ×(-2)
⇝(αβ + βƔ + Ɣα) = 6 + 3 + 2
⇝(αβ + βƔ + Ɣα) = 11 ⠀....1)
⇝ (αβƔ) = -2 × (-3) × (-1)
⇝ (αβƔ) = -6 ⠀....3)
- Formula for quadratic polynomial is:-
▶x³ -(α + β + Ɣ)x² + (αβ + βƔ + Ɣα)x -(αβƔ)
Putting values of (α + β + Ɣ), (αβ + βƔ + Ɣα) and (αβƔ) in the formula .
↛x³ -(-6)x² + (11)x - (-6)
↛x³ + 6x² + 11x + 6
Hence
The required cubic polynomial is:-
- x³ + 6x² + 11x + 6
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OR
Now,
substitute these values in eq.(1)
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