Question

find
a cubic pelynomial
polynomial whose zeros
are 3,1/2and -1!​

Answer 1

Answer:

SO THIS IS THE ANSWER

let A=3. ,beta =1/2 ,gamma=-1

( alpha+beta+gamma) =(3/2-1/2-3)

(alpha.beta+beta.gamma+gamma.alpha)=(3/2-1/2-3)

=( -4/2)

alpha beta gamma=3*1/2*(-1)

=(-3/2)

.

Here the required polynomial

x cube-(alpha+beta .gamma) x square+ alpha beta+beta gamma +gamma alpha)

x cube-5/2x square-2x+3/2

=2x cube-5x square -4x+3

I HOPE IT IS HELP YOU

Answer 2

pls reply me on ins ta plssss