Question

find a cubic polynomial when zeroes are 3, -1, -1/3​

Answer 1

Find a cubic polynomial whose zeros are  

3

,

5

and  

−

2

.

Solution

given roots are  

3

,

5

,

−

2

therefore the cubic equation with above roots are  

(

x

−

3

)

(

x

−

5

)

(

x

−

2

)

simplifying it we get

(

x

−

3

)

(

x

−

5

)

(

x

+

2

)

=

(

x

2

−

8

x

+

15

)

(

x

+

2

)

=

x

3

−

6

x

2

−

x

+

30

e

Answer 2

Answer:

the cubic polynomial is

(x-3)(x+1)(x+1/3)=0

(×^2+x-3x-3)(x+1/3)=0

(x^2-2x-3)(x+1/3)=0

x^3+1/3x^2-2x^2-2/3x-3x-1=0

x^3-5/3x^2-11/3x-1=0

3x^3_5x^2-11x-3=0

this is the correct answer