Find a cubic polynomial whose three zeroes are 0, 4 and -4.
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Answered by
1
Step-by-step explanation:
x cube -16x is the zero of the polynomial
Answered by
0
Step-by-step explanation:
ALPHA +BETA +GAMA =-b/a=0+4+(-4)=0
ALPHA BETA GAMA =-d/a=0×4×(-4)=0
ALPHA BETA +BETA GAMA +GAMA ALpha=c/a
=0+(-16)+0=-16 .... The FORMULA IS
=X^3-(alpha+beta+gama)X^2+(alpha beta +Beta gama+gama alpha) X-(alpha. Beta. Gama)
=X^3-(0)X^2+(-16)X-0
X^3-0-16x-0
X^3-16x=0
This is the equation
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