Find a cubic polynomial whose zeroes are 1 ,-2and 3
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Step-by-step explanation:
form of a Cubic polynomial -
ax³ + bx² + cx + d = 0
x³ + (b/a)x² + (c/a)x + (d/a) = 0
Let the roots of this polynomial are p , q & r .
So , p + q + r = -b/a
1 - 2 + 3 = -b/a
4 - 2 = -b/a
b/a = -2
&. pq + qr + rp = c/a
1(-2) + (-2)3 + 3(1) = c/a
-2 - 6 + 3 = c/a
c/a = -8+3 = -5
& also pqr = -d/a
1(-2)(3) = -d/a
-6 = -d/a
d/a = 6
At the end ,
The cubic polynomial is
x³ - 2x² - 5x + 6 = 0
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