find a cubic polynomial whose zeroes are 2,-3,4
Answers
Answered by
157
x³ -(sum of roots )x² + ( sum of products of two roots) x - product of all roots
let a , b and c are the roots of a polynomial so,
a + b + c = 2 -3 + 4 = 3
ab + bc + ca = 2×-3 + -3× 4 + 4× 2
= -6 -12 +8 = -10
abc = 2× -3 × 4 = -24
now,
polynomial is -----
x³-( a + b + c)x² + (ab +bc +ca)x -abc =0
x³ -3x² -10x + 24 = 0
let a , b and c are the roots of a polynomial so,
a + b + c = 2 -3 + 4 = 3
ab + bc + ca = 2×-3 + -3× 4 + 4× 2
= -6 -12 +8 = -10
abc = 2× -3 × 4 = -24
now,
polynomial is -----
x³-( a + b + c)x² + (ab +bc +ca)x -abc =0
x³ -3x² -10x + 24 = 0
Answered by
37
Let a=2,b=-3,c=4
Wkt,
x^3-x^2(a+b+c)-x(ab+bc+ca)+ABC
x^3-3x^2-10x-24
Wkt,
x^3-x^2(a+b+c)-x(ab+bc+ca)+ABC
x^3-3x^2-10x-24
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