Question

Find a cubic polynomial whose zeroes are 2, -3 and 5​

Answer 1

Step-by-step explanation:

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Answer 2

The given question is we have to find a cubic polynomial whose zeroes are 2, -3 and 5.

The general form of cubic polynomial is

${x}^{3} - (sum \: of \: zeroes) {x}^{2} + (sum \: of \: the \: product \: of \: zeroes)x - product \: of \: zeroes$

The sum of zeroes is

$2 - 3 + 5 = 4$

The product of zeroes is

$(2) \times ( - 3) \times (5) = - 30$

sum of the product of zeroes is

$2( - 3) + 2(5) + 5( - 3) \\ = - 6 + 10 - 15 \\ = - 21 + 10 \\ = - 11$

Then the final equation is

${x}^{3} - (4) {x}^{2} + ( - 11)x - 30 \\ {x}^{3} - 4 {x}^{2} + - 11x - 30$

# spj2

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