Find a cubic polynomial whose zeroes are a , b , y and a + B + y = 5 , ap + by + ya = -11 , aby = 3
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Step-by-step explanation:
Given -
- α + β + γ = 5
- αβ + βγ + γα = -11
- αβγ = 3
To Find -
- A cubic polynomial
Now,
As we know that :-
- α + β + γ = -b/a
→ 5/1 = -b/a ..... (i)
And
- αβ + βγ + γα = c/a
→ -11/1 = c/a ..... (ii)
And
- αβγ = -d/a
→ 3/1 = -d/a ...... (iii)
Now,
From (i), (ii) and (iii) we get :-
a = 1
b = -5
c = -11
d = -3
As we know that :-
For a cubic polynomial :-
- ax³ + bx² + cx + d
→ (1)x³ + (-5)x² + (-11)x + (-3)
→ x³ - 5x² - 11x - 3
Hence,
The required cubic polynomial is x³ - 5x² - 11x - 3
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