Question

find a cubic polynomial whose zeros are 3' 1/2 and -1

Answer 1

◀HERE'S YOUR ANSWER▶

The required cubic polynomial is
$= (x - 3)(x - \frac{1}{2})( x + 1) \\ = (x - \frac{1}{2} )(x - 3)(x + 1) \\ = (x - \frac{1}{2} )( {x}^{2} - 2x - 3) \\ = {x}^{3} - \frac{5}{2} {x}^{2} - 2x + \frac{3}{2} \\ = \frac{1}{2} ( {x}^{3} - 5 {x}^{2} - 4x + 3)$

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