Question

find a cubic polynomial whose zeros are 3, 1 by 2 - 1


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Answer 1

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Given: zeroes of a cubic polynomial 3,21,−1

By factor theorem,

(x−3)(x−21)(x+1) are the factors of the cubic polynomial.

We know that (x+a)(x+b)=x2+(a+b)x+ab 

Using the factors (x−3)(x−21) we have as

x2+(−3−21)x+23

=x2−2−7x+23

Again (x+1)(x2−27x+23)=x3−27x2+23x+x2−27x+2

Step-by-step explanation:

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