Question

find a cubic polynomial whose zeros are 3, 1 by 2 and -1​

Answer 1

Answer:-

Let the zeroes be denoted by a, b and c

Hence,

a + b + c = -b/a

= 3 + 1/2 - 1

= 2 + 1/2

= 5/2 ••••• (i)

ab + bc + ca = c/a

= ( 3 * 1/2 ) + ( 1/2 * -1 ) + ( -1 * 3 )

= 3/2 - 1/2 - 3

= 1 - 3

= -2

= -4/2 ••••• (ii)

abc = -d/a

= 3 * 1/2 * -1

= -3 * 1/2

= -3/2 ••••• (iii)

From (i), (ii) & (iii)

a = 2 , b = -5 , c = -4 , d = 3

Now cubic polynomial = ax³ + bx² + cx + d

= 2x³ - 5x² - 4x + 3

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Answer 2

Answer:

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