find। a cubic polynomial whose zeros are 3,-1and -1/3
Answers
Answered by
1
Given roots are 3, -1, -1/3
(x-3) (x+1)(x+1/3)
[x(x+1) -3(x+1)] (x+1/3)
[x²+x - 3x - 3] (x+1/3)
x [x²+x - 3x - 3] + 1/3 [x²+x - 3x - 3]
x^3 + x² - 3x² - 3x + 1/3x² + 1/3x -x -1
x^3 -5x²/3 - 11/3x - 1
(x-3) (x+1)(x+1/3)
[x(x+1) -3(x+1)] (x+1/3)
[x²+x - 3x - 3] (x+1/3)
x [x²+x - 3x - 3] + 1/3 [x²+x - 3x - 3]
x^3 + x² - 3x² - 3x + 1/3x² + 1/3x -x -1
x^3 -5x²/3 - 11/3x - 1
Similar questions