Question

find a cubic polynomial with the sum of product of each 0 taken two at a time and the product of its zeros as 2,-7,-14 respectively​

Answer 1

Let the polynomial be ax³ + bx²+ cx + d and the zeroes be α, β and γ

Then, α + β + γ = -(-2)/1 = 2 = -b/a αβ + βγ + γα = -7 = -7/1 = c/a αβγ = -14 = -14/1 = -d/a

∴ a = 1, b = -2, c = -7 and d = 14

So, one cubic polynomial which satisfy the given conditions will be x3 – 2×2 – 7x + 14

Thank you!

@itzshivani

Answer 2

Answer:

Hope it helps

Explanation:

Let the polynomial be ax3 + bx2 + cx + d and the zeroes be α, β and γ

Then, α + β + γ = -(-2)/1 = 2 = -b/a αβ + βγ + γα = -7 = -7/1 = c/a αβγ = -14 = -14/1 = -d/a

∴ a = 1, b = -2, c = -7 and d = 14

So, one cubic polynomial which satisfy the given conditions will be x3 – 2×2 – 7x + 14