Question

find a cubic polynomial with the sum of zeros,sum of product of zeros taken two at a time and product of its zeros are 2,-7and-14 respectively​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

$( \alpha + \beta + \gamma) {x}^{3} - ( \alpha \beta + \beta \gamma \ + \gamma \alpha ) {x}^{2} - ( \alpha \beta \gamma ) = 0 \\ \\ (2) {x}^{3} - ( - 7) {x}^{2} - ( - 14)x = 0 \\ 2 {x}^{3} + 7 {x}^{2} + 14x = 0$

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