Find a cubic polynomial with the sum , sum of the product of its zeros taken two at a time , and the product of its zeros as 2 , -7, -14 respectively
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2x+y=11 and 3x-4/4 a d 2x+y=11
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As We know that the cubic polynomial can be ax³+bx²+cx+d and the values of the zeroes of the polynomials be α, β, γ.
As We also know the different relations b/w the zeroes of the Polynomial.
→ α+β+γ = -b/a
→ α+β+γ = 2/1
→ αβ +βγ+γα = c/a
→ αβ +βγ+γα = –7/1
→ αβγ = -d/a
→ αβγ = –14/1
So now we got the values of coefficient of polynomial.
- a = 1, b = -2, c = -7, d = 14
Hence,
The cubic polynomial will be x³–2x²–7x+14.
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