Find a cubic polynomial with the sum sum of the product of its zeros taken two at a time and the product of zeroes has 2 - 7 - 14 respectively
Answers
Answered by
77
Answer:
Step-by-step explanation:
Sum of zeroes = 2
-b/a=2
Assuming a=1
b=-2
Sum of product of zeroes= -7
c/a= -7 (a=1)
c=-7
Product of zeroes =-14
-d/a=-14 (a=1)
d=14
So, a=1 , b=-2,c=-7,d=14
ax3+bx2+cx+d
x3-2x2-7x+14
Answered by
23
Answer:
Step-by-step explanation:
Step-by-step explanation:
Sum of zeroes = 2
-b/a=2
Assuming a=1
b=-2
Sum of product of zeroes= -7
c/a= -7 (a=1)
c=-7
Product of zeroes =-14
-d/a=-14 (a=1)
d=14
So, a=1 , b=-2,c=-7,d=14
ax3+bx2+cx+d
x3-2x2-7x+14
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