Question

Find a discriminant of the quadratic equation 4√2x^2+8x+2√2=0

Answer 1

AnsWer :

48.

Solution :

We have, Quadratic Equation.

$\tt \dagger \: \: \: \: \:4 \sqrt{2} {x}^{2} + 8x + 2 \sqrt{2} = 0.$

Compare with General Formula.

$\tt \dagger \: \: \: \: \: a {x}^{2} + bx + c = 0.$

$\tt \dagger \: \: \: \: \: D = {b}^{2} - 4ac.$

Here,

• D Discriminate.
• a = 4√2.
• b = 8.
• c = 2√2.

A/Q,

$\tt : \implies D = {\big(8\big)}^{2} - 4 \times 4 \sqrt{2} \times 2\sqrt{2} .$

$\tt : \implies D = 64 - 8 \times 2$

$\tt : \implies D = 64 - 16.$

$\tt : \implies D = 48.$

Therefore, the value of D is 48.

Answer 2

Answer: 48

                         

Step-by-step explanation:

                              discriminant of ax^2+bx+c =0  is b^2 -4ac

                                      here b=8 , a=4$\sqrt{2$ , c=2$\sqrt{2$

                                      then  = 64 -4( 4$\sqrt{2$ )(2$\sqrt{2$)

                                                  = 48