find a four digit number which when multiplied with 4 gives the opposite number
I.e. xyzw × 4=wzyx
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HEYA!!!
2178 is the desired number.
2178*4=8712.
P roof ==>
Lets say the number is written as ABCD (1000a+100b+10c+d).Multiplying it by 4, gives you DCBA(1000d+100c+10b+a)By divisibility of 4, BA is a two-digit number divisible by 4.Now, the largest possible value of ABCD is 2499, because anything more will result in a five digit number when multiplied by 4.Out of the two possibilites 1 and 2 for A, [3] follows that A is even, so 2.From [5], D is either 8 or 9. However, since D times 4 would end in 2, D is 8.Using [2], 4000a+400b+40c+4d = 1000d+100c+10b+a, which would simplify to 2c-13b = 1 after substituting A = 2 and D = 8.The only possible value of (b,c) where they would both be single digit integers is (1,7). Also to note from [3], B is odd. And from [4], B is either 1 or 3.
The answer you're looking for is 2178, multiplied by 4 gives 8712.
#KEVIN
HOPE IT HELPS YOU ☺
2178 is the desired number.
2178*4=8712.
P roof ==>
Lets say the number is written as ABCD (1000a+100b+10c+d).Multiplying it by 4, gives you DCBA(1000d+100c+10b+a)By divisibility of 4, BA is a two-digit number divisible by 4.Now, the largest possible value of ABCD is 2499, because anything more will result in a five digit number when multiplied by 4.Out of the two possibilites 1 and 2 for A, [3] follows that A is even, so 2.From [5], D is either 8 or 9. However, since D times 4 would end in 2, D is 8.Using [2], 4000a+400b+40c+4d = 1000d+100c+10b+a, which would simplify to 2c-13b = 1 after substituting A = 2 and D = 8.The only possible value of (b,c) where they would both be single digit integers is (1,7). Also to note from [3], B is odd. And from [4], B is either 1 or 3.
The answer you're looking for is 2178, multiplied by 4 gives 8712.
#KEVIN
HOPE IT HELPS YOU ☺
niti13:
but why ??
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