find a geometric progression for which sum of the 1st two terns is -4 and 5th term is 4times the 3rd term
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a1= -4
a5= 4(a+2d)
a5= 4×-4+8d
a+4d= -16+8d
-4+16= 8d-4d
12= 4d
d= 12/4
d= 3
therefore, we obtain a geometric progression as -4, -1, 2, 5,8_______
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