find a+ib from of
z=4√-4+5√-9-3√-16
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Answer:
0 + 11i
Step-by-step explanation:
z=4√-4 + 5√-9 - 3√-16
= 4√4i + 5√9i - 3√16i
= 4(2)i + 5(3)i - 3(4)i
= 8i + 15i - 12i
= 8i + 3i
= 11i
= 0 + 11i
I hope it helps please mark me as brainliest...
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