find a, if (3,a) line on the 2x-y-5=0
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Since (3,a) lie on the line 2x - 3y = 5 ...(1)
Substituting x=3 and y=a in (1) we get
2(3) - 3(a) = 5
6 - 3a = 5
⇒3a=1
⇒a=1/3.
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