Find a if 3-rootover 5 /3=2 rootover5 =-19/11+a rootover5
Answers
Step-by-step explanation:
It has given that, In an experiment to measure the diameter of a wire as measured by a screw gauge was found to be 0.026 cm, 0.028 cm, 0.027 cm, 0.024 cm, 0.027 cm, 0.029 cm.
To find :
mean value of the diameter
mean absolute error
relative error
percentage error of the above measurements.
solutiom : Observations are : 0.026 , 0.028, 0.027, 0.024, 0.027 , 0.029
Mean = sum of observations/number of observations
= (0.026 + 0.028 + 0.027 + 0.024 + 0.027 + 0.029)/6
= 0.0268 ≈ 0.027 cm
∴ mean value = 0.027 cm
Now, y₁ =|0.026 - 0.027| = 0.001
y₂ = |0.028 - 0.027| = 0.001
y₃ = |0.027 - 0.027| = 0.000
y₄ = |0.024 - 0.027| = 0.003
y₅ = |0.027 - 0.027| = 0.000
y₆ = |0.029 - 0.027| = 0.002
Now, absolue error ,∆y = (y₁ + y₂ + y₃ + y₄ + y₅ + y₆)/6
= (0.001 + 0.001 + 0.000 + 0.003 + 0.000 + 0.002)/6
= 0.007/6
= 0.00116
Now, relative error = absolute error/mean value
= 0.00116/0.027
= 0.04296
percentage error = relative error × 100
= 0.04296 × 100 = 4.296 ≈ 4.3 %