Question

Find a if 5a+2, 4a-1, a+2 are in A.P.

Answer 1

Answer :

Since, (5a + 2), (4a - 1) and (a + 2) are in AP,

(4a - 1) - (5a + 2) = (a + 2) - (4a - 1)

⇒ 4a - 1 - 5a - 2 = a + 2 - 4a + 1

⇒ - a - 3 = - 3a + 3

⇒ 3a - a = 3 + 3

⇒ 2a = 6

⇒ a = 6/2

⇒ a = 3

Therefore, the value of a is 3.

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Answer 2

Heya user!!!!
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Here's your answer :-

We know that in an AP, the common difference between consecutive terms is equal...

Since, the above equation is in AP...

Hence,

4a-1-(5a+2)=a+2-(4a-1)

=>4a-1-5a-2=a+2-4a+1

=>-a-3=-3a+3

=>-a+3a=6

=>2a=6

=>a=3

Hope this helps!!!

:-)