find a if m and n are the zeroes of the polynomial p(x)=ax^2-35x=12 and m^2+n^2=1
Answers
Hi.............
here's your answer................
given,
zeroes of the polynomial 3x²+11x -4 are m and n
⇒ 3(m)² + 11(m) -4 = 0
⇒ 3m²+ 11m -4 = 0
⇒ 3m² +12m -m - 4 = 0
⇒3m( m+ 4) - 1( m + 4) =0
⇒ (3m - 1) ( m+4) = 0
⇒ (3m - 1) = 0 (or) (m +4 ) = 0
⇒ m = 1/3 or m = -4
if we replace n in x place , we get the same values
Hence , m/n + n/m = 1 + 1 =2
-----------------------------—-----------------------------------------------------------------
hope it helps you........................
thanks
Answer:
Since m and n are the zeroes of the polynomial
p(x) = ax² - 35x - 12
So
m + n = 35/a
mn = - 12/a
Now
m² + n² = 1 gives
(m+n)² - 2mn = 1
( 35/a )² - 2 × (-12/a) = 1
a² - 24a - 1225 = 0
a² - (49-25)a - 1225 = 0
a² - 49a + 25a - 1225 = 0
a( a - 49) + 25 (a - 49) = 0
(a - 49) ( a + 25) = 0
Now (a - 49) = 0 gives a = 49
Again ( a + 25) = 0 gives a = - 25
So the required answer is - 25 , 49
Please Mark it Brainliest